Respuesta :

ujalakhan18

Answer:

[tex]\huge\boxed{\sf x =28 \textdegree}[/tex]

Step-by-step explanation:

Given that,

∠IAK = 62°

∠IAK + ∠IAD = 90° (Complementary angles)

62 + ∠IAD = 90°

Subtract 62 to both sides

∠IAD = 90 - 62

∠IAD = 28°

∠IAD = ∠ACB (Corresponding angles are equal)

So,

∠ACB = 28°

∠ACB = ∠GCJ (Vertically opposite angles are equal)

So,

28° = x°

OR

x° = 28°

[tex]\rule[225]{225}{2}[/tex]

Yeony2202

Answer:

28 degrees

Step-by-step explanation:

If two lines cross each other, it makes 4 angles, and 2 angles from opposite sides have the same length. Since line KL and line IJ crossed, angle KAI and angle LAJ will have the same angle.

--> Angle LAJ is 62 degrees

If we look closely, there is a triangle ABC, and since the question said that line KL and line FG is perpendicular, the angle ALG will be 90 degrees.

We know that in a triangle, there are three angles, and the angle measures combined equals 180.

Since we know two angles: 90 and 62, we take them away from 180 to find the last angle BCA.

--> 180 - 90 - 62 = 28

--> Angle BCA = 28 degrees

Like I said at the beginning, if two lines cross each other, opposite angles are the same size. So angle x will also be equal to angle BCA, which is 28 degrees.

Angle x = 28 degrees

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