Respuesta :
The mass (in grams) of precipitate is 0.6386 gram.
Calculation,
To find the mass of precipitate, first we have to find the precipitate. So, the chemical reaction when cesium hydroxide react to large excess of [tex]TiSO_{4}[/tex].
Mole of cesium hydroxide = given mass/molar mass = 2.34 gm/ 149.912 g/mol= 0.0156 moles
[tex]2CsOH+TiSO_{4}[/tex]→[tex]Ti(OH)_{2} +Cs_{2} SO_{4}[/tex]
So, mole ratio 2: 1
It means two moles of cesium hydroxide required to form one mole of titanium hydroxide.
To produce 0.0156 moles of cesium hydroxide = 0.0156 moles×1 mole/2
Mole of titanium hydroxide = 0.0078 mole
Mole of titanium hydroxide = given mass/molar mass of titanium hydroxide
Mole of titanium hydroxide = given mass/81.82 g/mol = 0.0078 mole
Mass of titanium hydroxide = 0.0078 mole ×81.88 g/mol = 0.6387 gm
learn about Precipitation
https://brainly.com/question/20925010?
#SPJ4
