contestada

A variable capacitor with a range from 12 to 279 pF is used with a coil to form a variable-frequency LC circuit to tune the input to a radio. (a) What is the ratio of maximum frequency to minimum frequency that can be obtained with such a capacitor

Respuesta :

Tutorconsortium330

The ratio of maximum frequency and minimum frequency is 4.9.

Calculation:

The relation between frequency, f, and conductance, C and inductance, L is given as:

[tex]f = \frac{1}{2\pi \sqrt{LC} }[/tex]

Given,

Cmax = 279 pF

Cmin = 12 pF

The smaller value of C gives the the larger value of f, therefore,

[tex]fmax = \frac{1}{2\pi\sqrt{LCmin} }[/tex]           ....(1)

[tex]fmin = \frac{1}{2\pi\sqrt{LCmax} }[/tex]           .....(2)

Dividing both the equations (1) and (2):

[tex]\frac{fmax}{fmin} =\frac{\sqrt{Cmax} }{\sqrt{Cmin} }[/tex]

[tex]\frac{fmax}{fmin} = \frac{\sqrt{279} }{\sqrt{12} }[/tex]

        [tex]= 4.9[/tex]

Hence, the ratio of maximum to minimum frequency is 4.9.

Learn more about the frequency calculation here:

https://brainly.com/question/18650584

#SPJ4

Otras preguntas