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2.6×10[tex]^-8[/tex] Ωm,A long, flat wire is used as a rear window defroster and is bonded to the window's interior surface.
Resistivity of the wire ?
Electrical resistivity is a measurement of a material's degree of resistance to current flow. The SI unit for electrical resistivity is the ohm meter (m). It is frequently represented by the Greek letter rho. Materials that easily transmit current and have a low resistance are called conductors.
Length of the wire, l = 12.2 m
width of the wire, w = 1.8 mm
Thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12 V
Current in battery, I = 7.5 A
Ohms law says, V = IR.
So that, R = V/I
R = 12/7.5 = 1.6 Ω
The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length.
Resistivity if a material is:
ρ = RA/l
ρ = [1.6 × 1.8 × 10[tex]^-3[/tex] × 0.11×10[tex]^-3[/tex]] / 12.2
ρ = (3.168×10[tex]^-7[/tex]) / 12.2
ρ = 2.596×10[tex]^-8[/tex]
Therefore, the resistivity of the wire is 2.60×10[tex]^-8[/tex] Ωm
Resistivity of the wire is 2.60*10^-8 Ωm
Given:
Length of the wire, I = 12.2 m
width of the wire, w = 1.8 mm
thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12
Current in the battery, I = 7.5 A
To Find:
Resistivity
Solution: A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents.
Remember, Ohms law says, V = IR
So that, RV/I
R = 12/7.5= 1.6 Q
Resistivity if a material is
p = RA/I
p = [1.6 * 1.8*10^-3* 0.11*10^-3] / 12.2
p = (3.168*10^-7)/12.2
p = 2.596*10^-8
Therefore, the resistivity of the wire is 2.60*10^-8 Ωm
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