Respuesta :

The wavelength of a photon if the energy is 7.69 × 10⁻¹⁹ J is

Calculation,

Given energy = 7.69 × 10⁻¹⁹ J

Plank's constant =  6.626 × 10⁻³⁴ J.s

Formula used:

E = hv

  • E is the energy
  • h is plank's constant
  • v s frequency

v = c/ lemda

Where, c = speed of light =

lamda = wavelength of the photon

Putting the value of v in equation (i), and rearrange the equation.

E = hc/lemda =  6.626 × 10⁻³⁴ J×3[tex]10^{8}[/tex]/lemda =  7.69 × 10⁻¹⁹ J.s

lamda = 6.626 × 10⁻³⁴J×3[tex]10^{8}[/tex] m[tex]s^{-1}[/tex]/7.69 × 10⁻¹⁹J.s = 2.58× [tex]10^{-9}[/tex]m =2.58 nm

So, wavelength of a photon is 2.58 nm

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