The density of the helium gas is 0.487 g/L
Calculation,
According to Ideal gas equation,
PV = nRT ...(I)
The values of some terms are given as,
P is the pressure = 3 atm
V is the volume = ?
T is the temperature = 27°C = 27°C + 273 = 300 K
R is the universal gas constant = 0.0821 L∙atm∙mol−1∙K−1
n is the number of moles of helium = given mass of helium/molar mass of helium
n is the number of moles of helium = 1 g/ 4 g/mole = 0.25 mole
So, by putting the value of all data given in the equation (i) we get,
3 atm × V = 0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K
V = 0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K/3 atm
V = 2.05 L
The formula of density = given mass /volume = 1g/2.05 L = 0.487 g/L
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