The 0.05 moles of [tex]Na_{3}PO_{4}[/tex] required to make 1 L of solution in which the [tex]Na[/tex] concentration is 0. 15 M.
Calculation,
The Sodium phosphate dissolves as follows:
[tex]Na_{3}PO_{4}(s)[/tex] → [tex]3Na^{+} (aq)+PO_{4}^{-} (aq)[/tex]
To make 1. L of solution in which the [tex]Na^{+[/tex]concentration is 0. 15 M
The morality of [tex]Na^{+[/tex]= 0.15 M = number of moles / volume in lit
The morality of [tex]Na^{+[/tex]= 0.15 M = number of moles /1 Lit
number of moles of [tex]Na^{+[/tex] = 0.15 mole
The mole ratio is 1: 3
It means, the 1 mole of [tex]Na_{3}PO_{4}(s)[/tex] required to form 3 mole of [tex]Na^{+[/tex]
So, to form 0.15 mole of [tex]Na^{+[/tex] = 1×0.15 / 3 moles of [tex]Na_{3}PO_{4}(s)[/tex]required.
Hence, number of moles of [tex]Na_{3}PO_{4}(s)[/tex] required = 0.05 moles.
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