If the length,breadth, height of cuboid are 16 m, 5 m,4 m , slant height of pyramid is 10m, height be 6 m then the surface area of composite figure be 444 [tex]m^{2}[/tex].
Given that the length,breadth,height of cuboid are 16m,5 m, 4m and slant height be 10 m and height be 6 m.
Surface area is basically sum of area of all the sides of a figure.
Surface area of composite figure = area of cuboid less area of common side + area of 2 slant sides of pyramid+area of two triangles.
=2(lb+bh+hl)-(lb)+2(slant height*breadth of cuboid)+2[1/2* length of cuboid* height of triangle)
=2(16*5+5*4+4*16)-16*5+2(10*5)+2[1/2*16*6]
=2(80+20+64)-80+2*50+2(48)
=2(164)-80+100+96
=328-80+196
=248+196
=444[tex]m^{2}[/tex]
Hence the surface area of composite figure having a cuboid and pyramid on top is 444[tex]m^{2}[/tex].
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