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A 1500 pound car is stopped in traffic on a hill that is at an incline of 10. The force that is required to keep the car from rolling down the hill will be 1133.53 N.
When all the forces that act upon an object are balanced, then the object is said to be in equilibrium motion. The forces are considered to be balanced if the rightward forces are balanced by the leftward forces and the upward forces are balanced by the downward forces.
It can be observed from the diagram that in order resist the car to rolling down the hill we need to apply an equal and opposite force against the inclined force( that is mgsin(x)) to form an equilibrium position because rolling is associated with horizontal forces hence we need to apply force against the force which can drive down the car .
mass = 1500 pound = 680.39 kg
sin(10) = 0.17
F (counter force ) = m*g*sin(x)
= 680.39 * 9.8 * 0.17
= 1133.53 N
To learn more about equilibrium motion
herehttps://brainly.com/question/4749763?referrer=searchResults
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