solve the differential equation

A differential equation is an equation that contains at least one derivative of an unknown function, either a normal differential equation or a partial differential equation.

We will solve this differential equation by using the integrating factor method.

Firstly, we will find the integrating factors by using the formula, we get

[tex]I.F=e^{\int Pdx}[/tex]

Here P=1/x and substitute this in the formula, we get

[tex]\begin{aligned}I.F.&=e^{\int \frac{1}{x}dx}\\ &=e^{\log x}\\ &=x\end[/tex]

Now, we will substitute the values in the formula

[tex]y\times I.F.=\int Q\times I.F.dx[/tex]

Here Q=x an substitute this in the above formula, we get

[tex]\begin{aligned}y\times x&=\int x\times xdx\\ yx&=\int x^{2} dx\\ yx&=\frac{x^3}{3}+C\end[/tex]

Further, we will divide both sides with x, we get

y=(x²/3)+(C/x) ......(1)

Given that y(1)=1 means when x=1 then y=1 so substitute this in equation (1) to find the value of C, we get

1=(1/3)+C

1-(1/3)=C

2/3=C

Substitute the value of C in equation (1), we get

y=(x²/3)+(2/(3x))

Now find the value of y when x=3, we get

y=(9/3)+(2/9)

y=3+(2/9)

y=29/9

Hence, in the differential equation y'+(y/x)=x for y(1)=1 then y(3) is 29/9.

Learn more about differential equation from here brainly.com/question/14865785

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