To produce a maximum emf of 1.0 V, the angular speed should rotate at 35.368 rad/s.
A uniform magnetic field is depicted by parallel straight lines that are distributed uniformly. The flux path is the same as the path of a tiny magnet's north-seeking pole. The flux channels are continuous, producing closed loops.
For a single loop of wire with a radius of 7.5 cm that rotates about a diameter in a uniform magnetic field of 1.6T. We need to determine the angular speed of rotation for it to produce a maximum electromotive force (emf) of 1.0 V.
Given that:
The radius = 7.5 cm, to convert it to meters, we will divide it by 100.
= (7.5/100) m
= 0.075 m
The area A of the wire is computed by using the formula:
A = πr²
A = π(0.075)²
A = 0.01767 m²
Imagine a coil with N turns with area A rotating at a constant angular velocity (q) inside a flux density of a (B) of a magnetic field, with its axis parallel to the field.
The maximum e.m.f can be computed by using the formula:
[tex]\mathbf{E_o = BAN \omega}[/tex]
Where;
Making the angular speed (ω) the subject of the formula, we have:
[tex]\mathbf{\omega =\dfrac{E}{BNA}}[/tex]
ω = 35.368 rad/s
Learn more about the angular speed of a uniform magnetic field here:
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