Given mass/molar mass = 64
Molar mass of methane = 16
Therefore,
No. of moles of methane = 64/16 = 4.
So, there are 4 moles of methane in 64amu of ch4.
Since, Avogadro's number= 6.022 * 10^23 i.e number of units in one mole of any substance)
We can also write 4* 6.022 * 10^23 molecules of methane [ one mole has weight as molecular weight in gm] .
Since each molecule has 10e, we can also write
10 * 4 * 6.022 *10^23 e in 64 gm of methane.
To learn more about molecular calculation in methane, here
brainly.com/question/24586870
#SPJ4
