The value of x from the given expression is [tex]\frac{5+\sqrt{29}}{2log2} \\[/tex]
Solving quadratic expression
Given the algebraic expression below;
2^x + 2^-x = 5
This can also be expressed as:
1/2^x+ 1/2^x = 5
Let P = 2^x, such that;
P + 1/P = 5
P²-1/P = 5
P²-1 = 5P
P²-5P-1=0
On factrorizing, then;
P = [tex]\frac{5+\sqrt{29}}{2} \\[/tex]
Since 2^x = P, then;
[tex]2^x=\frac{5+\sqrt{29}}{2} \\\\xlog2=\frac{5+\sqrt{29}}{2} \\\\x=\frac{5+\sqrt{29}}{2log2} \\[/tex]
Hence the value of x from the given expression is [tex]\frac{5+\sqrt{29}}{2log2} \\[/tex]
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