From the calculations, the power developed is 337.5 W.
First we must obtain the acceleration from;
v = u + at
u = 0 m/s because the motion started rom rest
v = at
a = v/t
a = 12 m/s/ 1.6 s
a= 7.5 m/s^2
The force is obtained from;
F = ma = 7.5 kg * 7.5 m/s^2 = 56.25 N
Now the distance covered is obtained from';
v^2 = u^2 + 2as
v^2 = 2as
s = v^2/2a
s = (12)^2/2 * 7.5
s = 9.6 m
Now;
Work = Fs = 56.25 N * 9.6 m = 540 J
Power expended = 540 J/ 1.6 s = 337.5 W
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