Answer:
1) x₁ = 0, x₂ = -10
2) x₁ = 3, x₂ = 4
Step-by-step explanation:
Given functions:
[tex]1)\ f(x)=x(x+10)[/tex]
[tex]2)\ f(x)=x(x-3)-4(x-3)[/tex]
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Zero Product Property: If m • n = 0, then m = 0 or n = 0.
Distributive Property: a(b + c) = ab + ac.
Standard Form of a Quadratic: ax² + bx + c = 0.
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The Zero Product Property
1) f(x) = x(x + 10)
Step 1: Set the function to zero.
[tex]\implies 0=x(x+10)[/tex]
Step 2: Apply the Zero Product Property.
[tex]\boxed{x_1=0}[/tex]
[tex]x+10=0\implies \boxed{x_2=-10}[/tex]
The solutions to this quadratic are: [tex]x_1=0,\ x_2=-10[/tex].
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The Zero Product Property
2. f(x) = x(x - 3) - 4(x - 3)
Step 1: Set the function to zero.
[tex]\implies 0 = x(x - 3) - 4(x - 3)[/tex]
Step 2: Factor out [tex]x- 3[/tex].
[tex]\implies 0 = (x - 3)(x - 4)[/tex]
Step 3: Apply the Zero Product Property.
[tex]x-3=0\implies \boxed{x_1=3}[/tex]
[tex]x-4=0 \implies \boxed{x_2=4}[/tex]
The solutions to this quadratic are: [tex]x_1=3,\ x_2=4[/tex].
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