Trigonometry, please provide a simple explanation

Answer:
C
Step-by-step explanation:
cosecΘ = [tex]\frac{1}{sin0}[/tex] = [tex]\frac{2}{\sqrt{3} }[/tex] ( cross- multiply )
2sinΘ = [tex]\sqrt{3}[/tex] ( divide both sides by 2 )
sinΘ = [tex]\frac{\sqrt{3} }{2}[/tex] , then
Θ = [tex]sin^{-1}[/tex] ( [tex]\frac{\sqrt{3} }{2}[/tex] ) = 60°
Answer:
C. 60°
Step-by-step explanation:
by definition, cosec(θ) is the reciprocal of sin(θ)
In other words ,
[tex]\text{cosec} \left( \theta \right) =\frac{1}{\sin \theta }[/tex]
Then
[tex]\text{cosec} \left( \theta \right) =\frac{2}{\sqrt{3} }[/tex]
[tex]\Longleftrightarrow \frac{1}{sin \left( \theta \right) } =\frac{2}{\sqrt{3} }[/tex]
[tex]\Longleftrightarrow sin \left( \theta \right) =\frac{\sqrt{3} } {2}[/tex]
Then
θ = 60°