Using the uniform distribution, the standard deviation of the timeout is of 34.64 seconds.
It is a distribution with two bounds, a and b, in which each outcome is equally as likely.
The standard deviation is:
[tex]S = \sqrt{\frac{(b - a)^2}{12}}[/tex].
For this problem, the bounds are:
a = 0, b = 120.
Hence the standard deviation is found as follows:
[tex]S = \sqrt{\frac{(120 - 0)^2}{12}} = 34.64[/tex].
More can be learned about the uniform distribution at https://brainly.com/question/13889040
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