Can someone help me out with these two problems having trouble please !!

Answer:
1.
x=-10
x=-6
2.
x=10
x=-3
Step-by-step explanation:
to find the zeros of a function you need to set it equal to zero:
x^2+16x+60=0
then you factor
(x+10)(x+6)=0
then you have to finish factoring/simplifying
x+10=0
-10
x=-10
x+6=0
-6
x=-6
and the same thing for number 2
x^2-7x-30=0
(x-10)(x-3)=0
x=10, x=3
Answer:
1.) x = -10, x = - 6
2.) x = 10, x = -3
Step-by-step explanation:
1.) factorize and set the equation to zero by multiplying a and c and finding factors of it that will result in b once added/subtracted
[tex]x^2+16x+60\\(x+10)(x+6)\\(x+10)(x+6)=0\\x=-10, x=-6[/tex]
2.) do the same for number 2:
[tex]x^2-7x-30\\(x-10)(x+3)\\(x-10)(x+3)=0\\x = 10, x = -3[/tex]
i hope this helped!