Answer:
Step-by-step explanation:
Given : 10 seat in first row, and the seat will increase 1 by 1 as we go above.... (as we go to the next row) - total rows - 38
Solve ; 38 rows, 10 seat in first row, 1 seat increases each row....
Extra seats - 37,
So,
37 x 10 = 370
TOTAL SEATS = 370
Answer:
1083 seats
Step-by-step explanation:
The number of seats is an arithmetic series with first term 10 and common difference 1. We want to find the sum of 38 terms of the series.
The sum of n terms of an arithmetic series with first term a1 and common difference d is given by the formula ...
Sn = (2a1 +d(n -1))(n/2)
The sum of the series of interest is ...
S38 = (2(10) +1(38 -1))(38/2)
The total number of seats in the theater can be found by evaluating the expression for S38:
S38 = (20 +37)(19) = 57×19 = 1083
There are 1083 seats in the theater.
