The solution to the system of equation is (0, 1)
System of equations
Given the following system of equation as shown below
2^(x)+3^(y)=5,
2^(x+2)+3^(y+1)=18
Rewrite
2^(x)+3^(y)=5,
2^x*2^2 + 3^y*3^1 = 18
___________
2^(x)+3^(y)=5,
4(2^x) + + 3(3^y) = 18
Let a = 2^x and b = 3^y
Substitute
a + b = 5
4a + 3b = 18
a = 5 - b
Substitute
4(5-b) + 3b = 18
20 - 4b + 3b = 18
-b = -2
b = 2
since a = 5 - b
a = 5 - 2
a = 3
Recall that a = 2^x and b = 3^y
2^x = 2
x = 0
Similarly
3^y = 3
y =1
Hence the solution to the system of equation is (0, 1)
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