Completing the squares, we have that:
- For the parabola of standard form y = x² - 6x + 17, we have that the equivalent form is (x - 3)² + 8 and the extreme value is (3,8).
- For the parabola of standard form y = x² + 8x + 21, we have that the equivalent form is (x + 4)² + 5 and the extreme value is (-4,5).
- For the parabola of standard form y = x² - 16x + 60, we have that the equivalent form is (x - 8)² - 4 and the extreme value is (8,-4).
What is the equation of a parabola given it’s vertex?
The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient.
For the parabola of standard form y = x² - 6x + 17, we have that it can be written as follows, completing the squares:
y = x² - 6x + 17 = (x - 3)² + 8, hence the extreme value is (3,8).
For the parabola of standard form y = x² + 8x + 21, we have that it can be written as follows, completing the squares:
y = x² + 8x + 21 = (x + 4)² + 5, hence the extreme value is (-4,5).
For the parabola of standard form y = x² - 16x + 60, we have that it can be written as follows, completing the squares:
y = x² - 16x + 60 = (x - 8)² - 4, hence the extreme value is (8,-4).
More can be learned about the equation of a parabola at https://brainly.com/question/17987697
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