two particles each having a mass of 5g and charge of 1.0×10^-7C stay in limiting equilibrium on a horizontal table with a separation of 10cm . The coefficient of friction between them and the table is same . Find the value of this coefficient.​

two particles each having a mass of 5g and charge of 10107C stay in limiting equilibrium on a horizontal table with a separation of 10cm The coefficient of fric class=

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The answer is μ=0.18.

What is meant by Friction?

  • A force that opposes this motion of the hands is activated when they brush against one another. The frictional force is the force resisting motion that is exerted in the direction that is counter to the direction that the hands are moving, and it is what creates heat energy.
  • The force that prevents one solid item from moving across another is known as friction. Static, sliding, rolling, and fluid friction are the four main categories of friction.
  • Many times, the uses of friction can be understood by imagining what would happen in their absence. You wouldn't be able to walk, operate a car, or grip anything if there was no friction. Pencils and pencils wouldn't function. Using brakes on a car or bicycle to halt requires friction as well.

Find the value of this coefficient.​

The particles are in equilibrium, meaning the net force on them is zero.

Thus, repulsion due to their charge = friction due to the table.

As the equilibrium is limiting, friction reaches its maximum value.

[tex]\frac{kQ^{2} }{r^{2} }[/tex]=μmg

[tex]k=9*10^{9} Nm^{2} C^{-2}[/tex]The electrostatic constant [tex]Q=10^{-7} C[/tex]  is the charge, and r=0.1m is the distance between the charges.

[tex]\frac{(9*10^{2})(10^{-7})^{2} }{(0.1)^{2} }[/tex]=μ*[tex](5*10^{-3})(10)[/tex]

Therefore, The answer is μ=0.18.

To learn more about friction, refer to:

https://brainly.com/question/24338873

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