(1)
Determine the equation of the line passing through the point (0; -1) and
parallel to the -axis. Do you remember what the gradient of this line is?

(2)
Determine the equation of the line passing through the point(-1;0) and
parallel to the -axis. Do you remember what the gradient of this line is?

Respuesta :

We know that,

slope = [tex] \rm{\frac{(y2 - y1)}{(x2 - x1)} }[/tex]

Let (0,1)=(x 1 ,y 1 ) and (1,2)=(x 2,y 2 )

So,

Slope of line = [tex] \frac{(2 - 1)}{(1 - 0)} = 1[/tex]

Now,

The required line equaqtion is given by,

==> y−y 1 = m(x-x1)

==> y−1=1(x−0)

==> y−1=x

==> y=x+1