The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
F = mv/t
where;
Ft = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
v² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
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