Respuesta :
Then the separation between the two pennies will be O.354m.
To find the correct answer, we need to know about the electrostatic force of attraction.
What is the separation between the pennies?
- We have given with the information's,
[tex]m=3*10^{-3}kg\\n=4*10^{12}\\[/tex]
- As we know that the charge of one electron is 1.6×10^-19C.Thus, the total charge on the penny will be,
[tex]Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1[/tex]
- We have the expression for electrostatic force of attraction as,
[tex]F_e=\frac{kQ_1Q_2}{r^2} =mg\\[/tex] , here given that the electrostatic force equal to the weight of the system.
- We have to find the separation between the pennies.
[tex]r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m[/tex]
Thus, we can conclude that the separation between the pennies is 0.354m.
Learn more about the electrostatic force here:
https://brainly.com/question/28108740
#SPJ1
0.354m will be the separation between the two pennies.
We must understand the electrostatic force of attraction in order to arrive at the correct solution.
How far apart are the pennies from one another?
- One electron has a charge of 1.6 10-19 coulombs, as is common knowledge. Consequently, the total fee for the penny will be,
[tex]Q_1=ne=4*10^{12}*1.67*10^{-19}=6.4*10^{-7}C\\Q_2=-Q_1[/tex]
- The expression of electrostatic force of attraction is as follows:
[tex]F=\frac{kQ_1Q_2}{R^2}=mg[/tex]
Given that the electrostatic force in this instance is equal to the system's weight.
- We must determine the distance between the pennies.
[tex]R=\sqrt{\frac{kQ_1Q_2}{mg} } =0.354m[/tex]
As a result, we may say that the distance between the pennies is 0.354m.
Learn more about electrostatic force here:
https://brainly.com/question/28108740
#SPJ1
