[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{What is the quadratic formula?}[/tex]
[tex]\rm{x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}[/tex]
[tex]\textsf{Or even}[/tex]
[tex]\rm{ax^2 + bx + c = 0}[/tex]
[tex]\huge\textbf{What are we looking for?}[/tex]
[tex]\rm{9x^2 + 3x - 2 = 0}[/tex]
[tex]\huge\textbf{What are the labels in the equation?}[/tex]
[tex]\mathsf{a \rightarrow 9}\\\\\mathsf{b\rightarrow 3}\\\\\mathsf{c \rightarrow -2}[/tex]
[tex]\huge\textbf{Solving for your equation:}[/tex]
[tex]\rm{x = \dfrac{-(3)\pm \sqrt{3^2 - 4(9)(-2)}}{2a}}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\rm{x = \dfrac{-3\pm \sqrt{81}}{18}}[/tex]
[tex]\rm{x = \dfrac{1}{3}\ or\ x = - \dfrac{2}{3}}[/tex]
[tex]\huge\textbf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{\frak{\mathsf{x} = \dfrac{1}{3}\ or\ \mathsf{x} = - \dfrac{2}{3}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
