The mechanical energy lost is 353.28 Joules . The distance he slid off is 0.16m.
we know:-
Mass = 69 kg
Speed = 3.2 m/s
Coefficient of friction ( ratio of friction force and normal force ) = 0.70
Acceleration due to gravity, g = 9.8 m/s^2
(a) To determine the amount of mechanical energy that is lost because of friction acting on the runner, we would calculate the change in kinetic energy:
[tex]KE = \frac{1}{2} m (v-u)^{2}[/tex]
[tex]= \frac{1}{2} 69 ( 3.2-0 )^{2}[/tex]
[tex]= 353.28[/tex] Joules
Mechanical energy = 353.28 Joules
(b) To determine how far (distance) the runner slide:
acceleration = ug
[tex]= 3.2[/tex] × [tex]9.8[/tex]
[tex]= 31.36[/tex] [tex]m/s^{2}[/tex]
distance ,
[tex]V^{2} = U^{2} + 2aS[/tex]
[tex]( 3.2)^{2} = 0 + 2 ( 31.36) S[/tex]
[tex]10.24 = 62.72 S[/tex]
[tex]S = {\frac{10.24}{62.72} }[/tex]
Distance, S = 0.16 m
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