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If the parabola of the form y = a(x – h)2 + k is always shifted horizontally h units and vertically k units, then its vertex is always

(–h, –k)

(h, k)

(–h, k)

(h, –k)

Respuesta :

The vertex of the transformed parabola with the equation [tex]y=a(x-h)^2+k[/tex] is (h, k).

What are the transformation rules for horizontal and vertical shifts?

The transformation rules are:

Translation: (x, y) → (x + a, y) or (x, y) → (x - a, y) (Horizontal shift)

Translation: (x, y) → (x , y + b) or (x, y) → (x , y - b) (Vertical shift)

Calculation:

It is given that, the transformed parabola is [tex]y=a(x-h)^2+k[/tex]

This parabola has vertex at (h, k).

Since this equation is obtained by shifting h units horizontally and k units vertically.

So, the original vertex is at (h - h, k - k) = (0, 0)

Thus, the equation of the actual parabola is [tex]y=ax^2[/tex]

Therefore, the given transformed equation of parabola has vertex (h, k).

Learn more about transformation rules here:

https://brainly.com/question/12537916

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