abbeygravatte abbeygravatte

25-07-2022
Mathematics

contestada

in this triangle, cosA/cosB =
AB = 4.24
BC= 3
AC = 3
<C 90deg.

in this triangle cosAcosB AB 424BC 3AC 3ltC 90deg class=

Respuesta :

Medunno13 Medunno13

29-07-2022

Answer:

1

Step-by-step explanation:

[tex]\cos A=\frac{3}{4.24} \\ \\ \cos B=\frac{3}{4.24} \\ \\ \frac{\cos A}{\cos B}=1[/tex]

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