Factoring the roots, the values of A and B are given as follows:
What are the values of A and B?
The expression is:
[tex]\sqrt{\frac{45\alpha z^3}{40y}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}[/tex]
We have that:
[tex]\frac{45}{40} = \frac{9}{8}[/tex]
Hence:
[tex]\sqrt{\frac{45\alpha z^3}{40y}} = \sqrt{\frac{9\alpha z^3}{8}} = \sqrt{\frac{9\alpha z^2 \times z}{4 \times 2}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}[/tex]
Hence, comparing the last two equalities:
More can be learned about the factoring of roots at https://brainly.com/question/24380382
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