The deceleration of the bullet over 0.2 second, given the data from the question is –2500 m/s²
What is acceleration?
This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time
NOTE: Deceleration is the opposite of acceleration
With the above equation for acceleration, we can obtain the deceleration of the bullet. Details below:
How to determine the deceleration of the bullet
- Initial velocity (u) = 500 m/s
- Final velocity (v) = 0 m/s
- Time (t) = 0.2 s
- Decelration (a) =?
a = (v – u) / t
a = (0 – 500) / 0.2
a = –500 / 0.2
a = –2500 m/s²
Thus, the deceleration of the bullet is –2500 m/s²
Learn more about acceleration:
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