Respuesta :

  • x/2+2y/3=-1

Multiply by 6

  • 3x+4y=-6-»eq(1)

And

  • x-y/3=3

Multiply by 3

  • 3x-y=9-»eq(2)

eq(1)-eq(2)

  • 5y=-15
  • y=-3

Then

  • 3x+4(-3)=-6
  • 3x-12=-6
  • 3x=6
  • x=2
DavidCopperfield

From Equation 1

[tex] \dfrac{x}{2} + \dfrac{2y}{3} = - 1 [/tex]

[tex] \dfrac{3x + 4y}{6} = - 1[/tex]

[tex]3x + 4y = - 6 [/tex]

From Equation 2

[tex]x - \dfrac{y}{3} = 3 [/tex]

[tex] \dfrac{3x - y}{3} = 3[/tex]

[tex]3x - y = 9[/tex]

By eliminating ;;

For that multiply equation 2 by 4

12x - 4y = 36 _(3)

By taking equation (1) and (3)

3x + 4y = -6

12x - 4y = 36

__________

15x = 30

x = 30/15

x = 2

Putting the value of x in 2

[tex]3(2) - y = 9[/tex]

[tex]6 - y = 9[/tex]

[tex]6 - 9 = y[/tex]

[tex]-3 = y[/tex]

So The value of x = 2 and y = -3

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