In the trapezoid below, AP = 6, PB = x + 3, CD = 2x + 6, AC = 10 and the area is 174. Find the value of x to the nearest tenth.​

In the trapezoid below AP 6 PB x 3 CD 2x 6 AC 10 and the area is 174 Find the value of x to the nearest tenth class=

Respuesta :

The value of x in the trapezoid given, to the nearest tenth, is: 10.5.

What is a Trapezoid?

A trapezoid is a quadrilateral that has two sides only that are parallel to each other.

What is the Area of a Trapezoid?

To find the area of a trapezoid, the formula used is expressed as: 1/2(a + b) × h, where:

  • a and b are length of the two base sides that are parallel.
  • h is the height of altitude of the trapezoid.

Given the following:

Area of trapezoid = 174 units²

AP = 6

PB = x + 3

CD = 2x + 6

AC = 10

Using the formula, we variables in the formula are:

a = AP + PB = 6 + x + 3 = x + 9

b = CD = 2x + 3

h = PC = √(AC² - AP²)

h = √(10² - 6²) = 8

Plug in the values into 1/2(a + b) × h:

174 = 1/2(x + 9 + 2x + 3) × 8

174 = 1/2(3x + 12) × 8

174 = (3x + 12) × 4

174 = 12x + 48

174 - 48 = 12x

126 = 12x

126/12 = x

10.5 = x

x = 10.5

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