The standard deviation is 0.1243, given the variance to be 0.01545, making option B the right choice.
Dispersion is measured by variance. A metric called a "measure of dispersion" is used to assess how variable data are concerning an average value. There are two sorts of data: grouped and ungrouped. Data is referred to as grouped data when it is presented as class intervals. On the other hand, it is referred to as ungrouped data if it comprises just individual data points. For both types of data, the sample and population variances may be calculated.
The variance of the provided data is obtained by taking the square of the standard deviation. The standard deviation is used to determine how widely distributed the data points are about the mean. In other words, the standard deviation is used to determine how observations in a data collection deviate from the mean. While the standard deviation has the same unit as the population or the sample, variance is represented in square units.
In the question, we are asked to find the standard deviation, if the variance is 0.01545.
We know that Variance = (Standard Deviation)².
This gives us:
Standard Deviation = √Variance,
or, Standard Deviation = √0.01545,
or, Standard Deviation = 0.12429802894 ≈ 0.1243.
Thus, the standard deviation is 0.1243, given the variance to be 0.01545, making option B the right choice.
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