The "barking dog" reaction is an exciting combustion reaction that generates a bright blue flame because sulfur is produced during the reaction (sulfur burns blue!). At the end of the reaction, a "woosh" sound is made which sounds like a dogs bark (hence the name of the reaction). Assume the reaction is carried out in a closed container. CS₂ + 4N₂0 CO₂ + SO₂ + S + 4N₂ Note: the equation is balanced How many moles of CO₂ can you generate if you were to carry out the reaction with 8.28 g CS₂?

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mickymike92 mickymike92 · Answer 1 · 2022-08-01T19:09:57+02:00

From the mole ratio CO₂ and CS₂ in the reaction, the moles of CO₂ produced is 0.109 moles.

The mole ratio of the reaction is the ratio in which the reactants combine to form products.

The mole ratio of the reaction is obtained from the equation of the reaction.

The equation of the reaction is given below:

Mole ratio of CO₂ and CS₂ is 1 : 1

Moles of CS₂ reacting = mass/molar mass

Molar mass of CS₂ is 76 g/mol

Mass of CS₂ reacting is 8.28 g

Moles of CS₂ reacting = 8.28/76

Moles of CS₂ reacting = 0.109 moles

Based on the mole ratio of the reaction, moles of CO₂ produced is 0.109 moles.

In conclusion, the moles of CO₂ produced is determined from the mole ratio CO₂ and CS₂ in the reaction.

Learn more about mole ratio at: https://brainly.com/question/19099163

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