The value of x in x^yz = y^2 is [tex]x = \sqrt[yz]{y^2}[/tex]
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
[tex]x^{yz} = y^2[/tex]
Take the yz root of both sides
[tex]\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}[/tex]
Apply the law of indices
[tex]x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}[/tex]
Divide yz by yz
[tex]x = \sqrt[yz]{y^2}[/tex]
Hence, the value of x in x^yz = y^2 is [tex]x = \sqrt[yz]{y^2}[/tex]
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Answer:
e
Step-by-step explanation:
Using euler's identity we can see that e^ipi=-1 and considering that i=y and i^2=-1 we can conclude that x=e
