The period of the function y = 2∕3 cos(4∕7x) + 2. is 7/2π
How to determine the period of the function?
The function is given as:
y = 2∕3 cos(4∕7x) + 2.
The above function is a cosine function
A cosine function is represented as:
y = A cos(B(x + C)) + D
Where the period is
Period = 2π/B
By comparing the equations, we have
B = 4/7
Substitute B = 4/7 in Period = 2π/B
Period = 2π/(4/7)
Express as product
Period = 2π * 7/4
Divide 4 by 2
Period = π * 7/2
Evaluate the product
Period = 7/2π
Hence, the period of the function y = 2∕3 cos(4∕7x) + 2. is 7/2π
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