The correct option for the matrix will be:
a) If an n x n matrix A has fewer than n distinct eigenvalues, then A is not diagonalizable.
It could have repeated eigenvalues as long as the basis of each eigenspace is equal to the multiplicity of that eigenvalue.
b) If A is diagonalizable the A2 is diagonalizable
If A is diagonalizable then there exists an invertible matrix
c) If Rn has a basis of eigenvectors of A, then A is diagonalizable.
d) A is diagonalizable if and only if A has n eigenvalues, counting multiplicity.
e) If A is diagonalizable, then A is invertible.
It’s invertible if it doesn’t have a zero as eigenvalue but this doesn’t affect diagonalizable.
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