The limiting reactant for the reaction between 27.3 g of iron and 45.8 g of oxygen is iron
We'll begin by writing the balanced equation for the reaction between iron and oxygen. This is given below:
4Fe + 3O₂ --> 2Fe₂O₃
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 4 × 56 = 224 g
Molar mass of O₂ = 16 × 2 = 32 g/mol
Mass of O₂ from the balanced equation = 3 × 32 = 96 g
SUMMARY
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂
The limiting reactant can be obtain as illustrated below:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂
Therefore,
27.3 g of Fe will react with = (27.3 × 96) / 224 = 11.7 g of O₂
From the calculation above, we can see that only 11.7 g of O₂ out of 45.8 g given is required to react completely with 27.3 g of Fe.
Thus, Fe is the limiting reactant.
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