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If you added 1 ml of an aqueous solution of NaCl at 0.4mol/l to 9ml of water what would be the final concentration of NaCl in the solution?

Respuesta :

Oseni

The final concentration of NaCl will be 0.04 mol/L.

Dilution principle

The dilution principle states that the number of moles of solute in a diluted solution remains the same as before dilution.

Mathematically, m1v1=m2v2

In this case, m1 = 0.4 mol/L, v1 = 1 mL, v2 = 1+9 = 10 mL

m2 = m1v1/v2 = 0.4 x 1/10 = 0.04 mol/L

Thus, the final concentration of the NaCl solution will be 0.04 mol/L.

More on dilution can be found here: https://brainly.com/question/21323871

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