Answer:
[tex]\text{f}(-3)=34[/tex]
Step-by-step explanation:
Given cubic function:
[tex]\text{f}(x)=-x^3+2x^2-11[/tex]
To find f(-3) substitute x = -3 into the given function:
[tex]\begin{aligned}\implies \text{f}(-3) & =-(-3)^3+2(-3)^2-11\\& =-(-3 \cdot -3 \cdot -3)+2(-3 \cdot -3)-11\\& = -(-27)+2(9)-11\\& = 27+18-11\\& = 45-11\\& = 34\end{aligned}[/tex]
