What is the mass of 9.3 x 1024
molecules of glucose, C6H12O6?
(C6H12O6; 180.18 g/mol)
[?] g C6H₁2O6
Mass (g)
Enter

Respuesta :

Answer:Molecular mass of  9.3 x 10^ 24 molecules of glucose  = 1675.6 x 10^ 24

It is given that the mass of glucose is 180.18 g/mol

so if we have to calculate the mass of 9.3x 10^ 24 molecules of glucose

we will apply a simple unitary method i.e,

9.3 x 10^ 24 *  180.18 g/mol = 1675.67 x 10^ 24

To calculate the molecular mass of a molecule, multiply the subscript (number of atoms) by the atomic mass of each element in the molecule and add those masses together.

Remember that - To determine the compound's molecular mass in grams per mole, use the molecular formula.

Divide the supplied mass by the molar mass of the chemical to convert it to moles.

By dividing the number of moles by Avogadro's number, you may convert from moles to molecules.

Explanation: