The required distance from the point (-10, -5) to the line y = -5x -3 is 2√26.
Given that,
To find the distance from the point (−10,−5) to the line y = −5x − 3.
A line can be defined by the shortest distance between two points is called a line.
Here,
The distance of a point [tex](x_1,y_1)[/tex] to the line ax + by +c =0. is given as
[tex]d = \frac{|ax_1+by_1+c|}{\sqrt{a^2+b^2} }[/tex]
Now. the distance from the point (−10,−5) to the line y = −5x − 3,
[tex]d = \frac{|5*10 - 5 + 3|}{\sqrt{5^2+1^2} }\\d = \frac{|5*10 - 5 + 3|}{\sqrt{5^2+1^2} }\\\\d = 52 /\sqrt{26} \\d=2 * 26 / \sqrt{26} \\d = 2\sqrt{26}[/tex]
Thus, the required distance from the point (-10, -5) to the line y = -5x -3 is 2√26.
learn more about lines here:
brainly.com/question/2696693
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