The required area of the triangle ABC is 67.30.
Given that,
AB = 14 ft, BC = 10 ft, and ∠ABC = 74
The area of triangle ABC to the nearest tenth is to be determined.
The triangle is geometric shape that includes 3 sides and the sum of the interior angle should not greater than 180°.
Here,
Area of the triangle = 1/2 bc sin75
= 1 / 2 * 14 * 10 * sin 75
= 67.30
Thus, the required area of the triangle ABC is 67.30.
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