a)We know that first equation of motion V=u+at
Here initial velocity is zero, u=0
and V=5 m/s
a= 4 m/s²
5=0+4t
5=4t
t=5/4=1.25 s
The car to travel the given distance it take 1.25 s.
We know that third equation of motion V^2 =u^2+2as
Putting all values in above equation we get
V^2=0+2[tex]\times[/tex]4[tex]\times[/tex]348
V^2= 2784
V= 52.76 m/s
The speed of the car at the end of this time 52.76 m/s.
What is distance?
- Distance and displacement are two variables that appear to represent the same thing but have quite different meanings and definitions.
- Distance is defined as "how much ground an item has covered throughout its motion," whereas displacement is defined as "how far out of position an object is." Let us examine the distinction between distance and displacement in this essay.
- Distance is defined as an object's entire movement without regard for direction. Distance may be defined as how much ground an item has traversed regardless of its starting or finishing place.
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