If the concentration of mercury in the water of a polluted lake is 0.200 μg (micrograms) per liter of water, what is the total mass of mercury in the lake, in kilograms, if the lake has a surface area of 17.0 square miles and an average depth of 39.0 feet?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operations.

* Multiplication operation: Multiplies values on either side of the operator

For example 12*2 = 24

The volume of water in the lake = surface area x depth

= 17 x ( 1760 x 3 )² x 39 ft³

= 1.84 x 10¹⁰ ft³

= 1.84 x 10¹⁰ x 28.3168 liter .

= 52.339 x 10¹⁰ liter .

Since concentration of mercury = 0.20 x 10⁻⁶ g / liter

= 20 x 10⁻⁸ g / liter

= 20 x 10⁻¹¹ kg / liter

So the mass of mercury in the water of the lake

= 20 x 10⁻¹¹ x 52.339 x 10¹⁰ kg

= 104.67 kg .

Hence, the total mass of mercury in the lake is 104.67 kg.

Learn more about Arithmetic operations here:

brainly.com/question/25834626

#SPJ1