The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.
It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.
Frequency = 1/time period of the oscillation
Frequency of the tuning fork = 1/time period
=1/2.50×10⁻³
=400 Hz
Thus the frequency of a tuning fork comes out to be 400 Hz.
Learn more about frequency here, refer to the link;
brainly.com/question/14316711
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