Answer:
1/15
Step-by-step explanation:
The two events are not dependent so we can not use multiplication rule.
So P(getting a quarter on the first try) is
[tex] \frac{3}{10} [/tex]
Assuming we get a quarter, we would be left with 9 coins, and only 2 quarters, so
P(getting a quarter second time in a row)
[tex] \frac{2}{9} [/tex]
Multiply the two
[tex] \frac{3}{10} \times \frac{2}{9} = \frac{6}{90} = \frac{1}{15} [/tex]