The probability of randomly chosen tall and obese individuals is 0.30.
Firstly complete the given table and find the total of each row and column.
Tall Medium Short Total
Obese 18 28 14 60
Normal 20 51 28 99
Underweight 12 25 9 46
Total 50 104 51 205
We have to find P(Tall | Obese).
P(Tall | Obese) = P(Tall and Obese) / P(Obese)
Now, P(Tall and Obese) = 18 ÷ 205
And, P(Obese) = 60÷205
Substituting the above values,
P(Tall | Obese) = 18÷205/ 60÷205
P(Tall | Obese) = 18/60
P(Tall | Obese) = 0.30
Hence the probability of a tall and obese individual is 0.30.
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