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Motion of a particle along a straight line is given by the acceleration-time relation a=1-21 +2. After 1 second, the distance traveled by the particle and the velocity of the particle were found to be 14.75 in and 6-33 m/s, respectively. Find after 2 seconds distance traveled, and velocity

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onyebuchinnaji

After 2 seconds distance traveled is 31.59 m, and the velocity is 15.8 m/s.

Acceleration of the particle

The acceleration of the particle is calculated as follows;

s = ut + ¹/₂at²

14.75 = 6.33(1) + 0.5(a)(1)²

14.75 = 6.33 + 0.5a

8.42 = 0.5a

a = 8.42/0.5

a = 16.84 m/s²

Position of the particle after 2 seconds

s = ut + ¹/₂at²

s = 6.33(2) +  0.5(16.84)(2)²

s = 46.34 m

Distance traveled from 1 second to 2 second = 46.34 m - 14.75 m = 31.59 m.

velocity = 31.59 m / 2 s = 15.8 m/s

Thus, after 2 seconds distance traveled is 31.59 m, and the velocity is 15.8 m/s.

Learn more about distance traveled here: https://brainly.com/question/2854969

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